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Thermochemistry &
Hess's Law |
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This
experiment will ask students to investigate thermochemistry
and Hess's Law (SCSCPS, p 33). Introduction In this experiment we
will determine the enthalpy change in two chemical reactions ((1) and (2)
below) and then use Hess's Law to calculate the enthalpy for the third
reaction. ((3) below).We will then determine the
enthalpy for the third reaction and compare the experimental value to the
calculated value. Thus, the calculated
value becomes our hypothesis in this experiment. The
molecular equations for the reactions are as follows: (1)
NaOH(aq) + HCl(aq) à NaCl(aq) + H2O(l) (2)
NH4Cl(aq) + NaOH(aq) à NH3(aq) + NaCl(aq) + H2O(l) (3)
NH3(aq) + HCl(aq) à NH4Cl(aq) Heat
cannot be measured as can mass with a balance or temperature with a
thermometer. It is possible, however,
to determine the heat change that occurs as a result of a chemical reaction.
The change in heat is calculated from the mass, temperature change, and the
specific heat of the substance which gains or loses heat. The
equation that is used to calculate heat gain or loss is as follows: q
= (grams of substance) X (specific heat) x ΔT where: q
= the heat energy gained or lost, ΔT
= the change in temperature (T2 - T1). specific
heat = the specific heat or heat capacity of the substance in which the
reaction was performed (usually water at 4.18 J/g °C) Acid-base
neutralization is an exothermic process. Combining solutions containing an
acid and a base results in a rise of solution
temperature. The heat given off by the reaction (which will cause the
solution temperature to rise) can be calculated from the specific heat of the
solution, the mass of solution and the temperature change. This heat quantity
can then be converted to the enthalpy change for the reaction in terms of
kJ/mole by using the concentrations of the reactants. According
to Hess's Law, if a reaction can be carried out in a series of steps, the sum
of the enthalpies for each step should equal the enthalpy change for the
entire reaction. Another way of stating "Hess's Law" is: If two
chemical equations can algebraically be combined to give a third equation,
the values of ΔH for the two equations can be combined in the same manner to give ΔH for the third
equation. We
can see in the acid -base equations shown above that if equation (2) is
subtracted from equation (1), equation (3) will result. Therefore, if the
value of ΔH for equation (2)
is subtracted from that of equation (1), the enthalpy change for equation (3)
should result. |
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Materials
& Methods Materials: Hydrochloric acid, 3.0 M Ammonium chloride, 3.0 M Sodium hydroxide, 3.0 M Ammonium hydroxide, 3.0 M Equipment: Calorimeter made from
two nested styrofoam cups thermometer (0 to
110°C) 25-mL graduated
cylinder Procedure: 1. Set
up calorimeter (two nested styrofoam cups) with
thermometer. 2. Obtain
25.0 mL of 3.0 M HCl and
add to calorimeter. Determine
temperature to nearest 0.2°C. 3. Rinse graduated cylinder and obtain
25.0 mL of 0.3 M NaOH. Determine temperature to nearest
0.2°C. If the temperature for the two solution does not agree, then average the two temperature
and use that as your initial temperature. 4. Add the 3.0 M NaOH
to the 3.0 M HCl in the calorimeter. Stir the solution with the thermometer and
record the temperature to nearest 0.2°C every 20 seconds for 3.0 min. 5. Repeat the above process with the
reactants in equations (2) and (3). Be
sure that the containers are rinsed between each set of reactions. Discard the solutions in the sink. Calculations: 1. For each of the three reactions
prepare a graph of temperature versus time (x-axis). Extrapolate back to to zero time to find the instantaneous temperature of
mixing 2. Calculate the heat of the reaction for
each of the three reactions using the following equation: Heat
= Sp. Heat H2O x density of solution (1.05g/mL) x volume x ΔT 3. Use Hess's Law to predict the
enthalpy for reaction (3). Compare
your predicted value with the value you measured. Results: Show your three graphs to determine
the initial temperature of mixing.
Show your enthalpy calculations. Safety: This procedure involves the use of
strong acid and base (alkali) solutions.
Wear goggles at all times.
Dispose of chemicals properly. Discussion/Conclusions: In your discussion/conclusion section of your report discuss specifically how the
results relate obtained for reaction (3) compare to the predicted value for
reaction (3). Be sure to discuss
potential sources of error (especially heat loss not accounted for) in your
experiment and how the experiment might be improved or modified to obtain
better results. Questions 1. In this
experiment we used a specific heat for the solution that was equal to that of
water. How would you expect a salt
solution to alter the specific heat of water and why? Think in terms of how the polarity of water
influences the nature of water. 2. If a mixed
solution has a density of 1.02 g/mL and is formed
by mixing 35 mL of A and 55 mL
of B, both initially at 22.4°C, what will be the enthalpy of the reaction if
the temperature of the combined solution rises to 29.4°C? 3. What will
be the temperature that results from mixing three volumes of water, the first
being 25 mL at 34.4°C, the second being 35 mL at 74.8°C, and the third being 85 mL
at 14.6°C? 4. Given the
following information: O3
(g) + NO (g) à NO2 (g) + O2 (g) ΔH = -199 kJ O2
(g) à 2 O ΔH
= +495 kJ 2
O3 (g) à 3 O2 (g) ΔH = -427 kJ use
Hess's Law to calculate the ΔH for the reaction: NO
(g) +
O (g) à NO2 (g) 5. Look up
the heats of formation for the neutralization reaction involving HCl and NaOH in equation (1) in
the introduction and calculate the enthalpy for the reaction. Compare this
result to the result that you actually measured. Be sure to take into account the
concentration and volumes of the solutions involved. |
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